If it's not what You are looking for type in the equation solver your own equation and let us solve it.
m^2-3.5m=1.5
We move all terms to the left:
m^2-3.5m-(1.5)=0
We add all the numbers together, and all the variables
m^2-3.5m-1.5=0
a = 1; b = -3.5; c = -1.5;
Δ = b2-4ac
Δ = -3.52-4·1·(-1.5)
Δ = 18.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.5)-\sqrt{18.25}}{2*1}=\frac{3.5-\sqrt{18.25}}{2} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.5)+\sqrt{18.25}}{2*1}=\frac{3.5+\sqrt{18.25}}{2} $
| 200x=-10x(-10x) | | 11x2=x2+8x | | a+1.8=6.2 | | Y=x+2x-20 | | -(x+-1)+5=2(x+3)+1 | | -3(f+-7)=-24 | | -(x+-1)+5=2(x+3)+5 | | 28=4y+9y-6y | | 5x+12=x-28 | | (1/2)10x^2+20x=480 | | –3(f+–7)=–24 | | 3r–7=2(4–3r) | | 14z-4z=-30 | | 15x=19x+380 | | v/5+7=9 | | 12.75w+114.25=25 | | b−97/–2=–1 | | 11x+x+2=32 | | 1(x+-3)+2x=-(x+-5)+4 | | 6(q+5)=42 | | 51=43+x94 | | (7^-2x)-1=59 | | 3u−1=8 | | -1(x+-3)+2x=-(x+-5)+4 | | 3(x+-3)+2x=-(x+-5)+4 | | 6^2+14^2=c^2 | | a/3+9=14 | | -3(x+-3)+2x=-(x+-5)+4 | | 5b+b=-12 | | 5m+5=-75 | | 3(x+-3)+2x=-1(x+-5)+4 | | 19/7=n/10 |